curl request in java umwandeln ~ Silberblatt

vendredi 29 mai 2015

curl request in java umwandeln

Posted on 02:38 by verona

Hallo Zusammen

Ich habe folgende cURL request:

curl -ikX POST -d "{\"outboundSMSMessageRequest\":{\"senderAddress\":\"tel:+40000000000\", \"address\":[\"tel:+4179xxxxxxx\"],\"outboundSMSTextMessage\":{\"message\":\"The Message\"},\"clientCorrelator\":\"any id\"}}" -H "Content-Type:application/json" -H "Accept:application/json" -H "client_id: %YOUR_CLIENT_ID%" http://ift.tt/1HA0oru

Meine Aufgabe ist es, dass in Java zu realisierten, also eine Java Klasse zu schreiben.

Ich habe folgende Java-Klasse geschrieben:

Java Code:

package sms;
import java.io.BufferedReader;
import java.io.DataOutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.ProtocolException;
import java.net.URL;
import java.net.URLEncoder;
import com.google.gson.Gson;
/**
*
* @author Behar
* Sms senden
*/
public class Sms {
private String to; //Telefonnummer
private String text; //Nachricht
private int tokenLength; //??
private String expireTime; //?
/**
* @param apiKey
* @param sms
* @throws IOException
*/
public static void senden (String apiKey, Sms sms) throws IOException {
try{
//Json Parameter erstellen
Gson gson = new Gson();
String json = gson.toJson(sms);
//URL
URL url = new URL("http://ift.tt/1HR1cxL;);
//Verbindung offnen
HttpURLConnection con = (HttpURLConnection) url.openConnection();
//Methode
con.setRequestMethod("POST");
//Header setezn
con.setRequestProperty("client_id", apiKey);
con.setRequestProperty("Accept", "application/json; charset=utf-8");
con.setRequestProperty("Content-Type", "application/json; charset=utf-8");
con.setDoOutput(true);
//Json data im Body hinzufügen
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
String param = "json=" + URLEncoder.encode(json, "UTF-8");
wr.write(param.getBytes());
System.out.println(json);
wr.flush();
wr.close();
// Get the response
int responseCode = con.getResponseCode();
System.out.println("\nSending 'POST' request to URL : " + url);
System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(
new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
// 7. Print result
System.out.println(response.toString());
}
catch (MalformedURLException e) {
e.printStackTrace();
}
}
//Getter und Setter Methoden
/**
*
* @return Nachricht
*/
public String getTo() {
return to;
}
/**
*
* @param to Telefonnummer des Senders
*/
public void setTo(String to) {
this.to = to;
}
/**
* @return Nachricht
*/
public String getText() {
return text;
}
public void setText(String text) {
this.text = text;
}
public int getTokenLength() {
return tokenLength;
}
public void setTokenLength(int tokenLength) {
this.tokenLength = tokenLength;
}
public String getExpireTime() {
return expireTime;
}
public void setExpireTime(String expireTime) {
this.expireTime = expireTime;
}
}

Leider funktioniert die Klasse nicht ganz.
Ich bekomme Response Code : 400

Ich glaube es stimmt mit den Parametern etwas nicht.

Klasse senden:

Java Code:

package sms;
import java.io.IOException;
publicclassSend {
public static void main (String [] arg) throws IOException {
Sms sms = new Sms();
sms.setText("Hallo Test");
sms.setTo("+41791749697");
sms.setTokenLength(8);
sms.setExpireTime("60");
Sms.senden("?? :)", sms);
}
}

Ich wäre euch sehr dankbar wenn ihr mir weiterhelfen könntet

Danke im Voraus!

curl request in java umwandeln

Categories: curl request in java umwandeln

Silberblatt

vendredi 29 mai 2015

curl request in java umwandeln

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